What is the tangent of 6x^2-4xy+4y^2-14=0,(1,2) ?

The tangent of 6x^2-4xy+4y^2-14=0,(1,2) is y=-1/3 x+7/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 6x^2-4xy+4y^2-14=0,(1,2)

tangent of

6 x^{2} - 4 x y + 4 y^{2} - 14 = 0, (1, 2)

y = - \frac{1}{3} x + \frac{7}{3}

Solution steps

Find the slope of

6 x^{2} - 4 x y + 4 y^{2} - 14 = 0 : \frac{d y}{d x} = \frac{- 3 x + y}{- x + 2 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(1, 2) : y = - \frac{1}{3} x + \frac{7}{3}

y = - \frac{1}{3} x + \frac{7}{3}

y = x + 1, (8, 3)

f (x) = x^{4} - 2 x^{3} + x - 1

\frac{d}{d t} (e^{r (t) t})

- x^{2} + 9 x, x^{2} - 5 x

y = 3 - 5 x

What is the tangent of 6x^2-4xy+4y^2-14=0,(1,2) ?
The tangent of 6x^2-4xy+4y^2-14=0,(1,2) is y=-1/3 x+7/3