What is the derivative of-2cos(2x) ?

The derivative of-2cos(2x) is 4sin(2x)

What is the first derivative of-2cos(2x) ?

The first derivative of-2cos(2x) is 4sin(2x)

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derivative of

- 2 cos (2 x)

4 sin (2 x)

Solution steps

\frac{d}{d x} (- 2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 2 (- sin (2 x) \cdot 2)

Simplify

= 4 sin (2 x)

f (x) = 2 5^{x}

\int - 6 x (- 4 x^{2} + 6)^{5} d x

\int \frac{9}{15 sin ( x ) - 8 cos ( x )} d x

\frac{d}{d x} (\frac{2 x}{a ^{2} - x ^{2}})

n = 1 \sum \infty \frac{1}{4 n ^{2} + 7}

What is the derivative of-2cos(2x) ?
The derivative of-2cos(2x) is 4sin(2x)
What is the first derivative of-2cos(2x) ?
The first derivative of-2cos(2x) is 4sin(2x)