What is the integral of 7xsin(2x) ?

The integral of 7xsin(2x) is 7(-1/2 xcos(2x)+1/4 sin(2x))+C

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integral of 7xsin(2x)

\int 7 x sin (2 x) d x

7 (- \frac{1}{2} x cos (2 x) + \frac{1}{4} sin (2 x)) + C

Solution steps

\int 7 x sin (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int x sin (2 x) d x

Apply Integration By Parts

: - \frac{1}{2} x cos (2 x) - \int - \frac{1}{2} cos (2 x) d x

= 7 (- \frac{1}{2} x cos (2 x) - \int - \frac{1}{2} cos (2 x) d x)

\int - \frac{1}{2} cos (2 x) d x = - \frac{1}{4} sin (2 x)

= 7 (- \frac{1}{2} x cos (2 x) - (- \frac{1}{4} sin (2 x)))

Simplify

= 7 (- \frac{1}{2} x cos (2 x) + \frac{1}{4} sin (2 x))

Add a constant to the solution

= 7 (- \frac{1}{2} x cos (2 x) + \frac{1}{4} sin (2 x)) + C

x \to 2 - lim (\frac{2}{2 - x})

t \to 2 lim (ln (t^{3}))

(\frac{1}{x}) d y = sin (x) (y^{3} + y) d x

x \to 0 - lim (e^{- x})

f (x) = \frac{7}{x}, at x = 2, x = 7

What is the integral of 7xsin(2x) ?
The integral of 7xsin(2x) is 7(-1/2 xcos(2x)+1/4 sin(2x))+C