What is the derivative of f(x)=-2ln(x)+x^2-4 ?

The derivative of f(x)=-2ln(x)+x^2-4 is 2x-2/x

What is the first derivative of f(x)=-2ln(x)+x^2-4 ?

The first derivative of f(x)=-2ln(x)+x^2-4 is 2x-2/x

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derivative of

f (x) = - 2 ln (x) + x^{2} - 4

2 x - \frac{2}{x}

Solution steps

\frac{d}{d x} (- 2 ln (x) + x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 ln (x)) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= - \frac{2}{x} + 2 x - 0

Simplify

= 2 x - \frac{2}{x}

e^{x} y d y - (e^{- y} + e^{- 2 x - y}) d x = 0

\int - 2 e^{4 x} d x

\frac{\partial}{\partial x} (x^{- 1})

\frac{s + 2}{s ( s + 1 ) ( s + 3 )}

\frac{\partial}{\partial x} (sin (2 x) + cos (3 y))

What is the derivative of f(x)=-2ln(x)+x^2-4 ?
The derivative of f(x)=-2ln(x)+x^2-4 is 2x-2/x
What is the first derivative of f(x)=-2ln(x)+x^2-4 ?
The first derivative of f(x)=-2ln(x)+x^2-4 is 2x-2/x