What is the integral from-32 to 2 of 1/(sqrt(|2x|)) ?

The integral from-32 to 2 of 1/(sqrt(|2x|)) is 10

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integral from-32 to 2 of 1/(sqrt(|2x|))

\int_{- 32}^{2} \frac{1}{∣ 2 x ∣} d x

10

Solution steps

\int_{- 32}^{2} \frac{1}{∣ 2 x ∣} d x

Eliminate Absolutes

= \int_{- 32}^{0} \frac{1}{- 2 x} d x + \int_{0}^{2} \frac{1}{2 x} d x

\int_{- 32}^{0} \frac{1}{- 2 x} d x = 8

\int_{0}^{2} \frac{1}{2 x} d x = 2

= 8 + 2

Simplify

= 10

y^{^{'}} = \frac{( y - x y )}{x ^{2}}

ln (3 x)

\int 4 x ln (y) d x

- 3 x^{3} - 2 x^{2} - 1, at x = - 1

\frac{d}{d x} (y sin (z (x)))

What is the integral from-32 to 2 of 1/(sqrt(|2x|)) ?
The integral from-32 to 2 of 1/(sqrt(|2x|)) is 10