What is the derivative of ln(x^2+4) ?

The derivative of ln(x^2+4) is (2x)/(x^2+4)

What is the first derivative of ln(x^2+4) ?

The first derivative of ln(x^2+4) is (2x)/(x^2+4)

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derivative of

ln (x^{2} + 4)

\frac{2 x}{x ^{2} + 4}

Solution steps

\frac{d}{d x} (ln (x^{2} + 4))

Apply the chain rule:

\frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

= \frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= \frac{1}{x ^{2} + 4} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 4} \cdot 2 x : \frac{2 x}{x ^{2} + 4}

= \frac{2 x}{x ^{2} + 4}

x \to 0 lim (2 f (x) - 1)

y^{^{''}} + 16 y = 4 t^{2}

\int \frac{x ^{4} + 9}{x ^{2} + 9 x ^{2}} d x

x \to 0 lim ((1 + 2 x)^{- \frac{3}{x}})

\frac{\partial}{\partial x} (sin (π (5 x - 5 y)))

What is the derivative of ln(x^2+4) ?
The derivative of ln(x^2+4) is (2x)/(x^2+4)
What is the first derivative of ln(x^2+4) ?
The first derivative of ln(x^2+4) is (2x)/(x^2+4)