What is the solution for (d^2)/(dx^2)y=sin(x) ?

The solution for (d^2)/(dx^2)y=sin(x) is y=-sin(x)+c_{1}x+c_{2}

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(d^2)/(dx^2)y=sin(x)

\frac{d ^{2}}{d x ^{2}} y = sin (x)

y = - sin (x) + c_{1} x + c_{2}

Solution steps

\frac{d ^{2} y}{d x ^{2}} = sin (x)

Solve

y^{''} (x) = sin (x) : y^{'} (x) = - cos (x) + c_{1}

Solve

y^{'} (x) = - cos (x) + c_{1} : y = - sin (x) + c_{1} x + c_{2}

y = - sin (x) + c_{1} x + c_{2}

\int (2 x^{3}) d x

y^{^{'}} + 2 y = 5

\frac{3 x}{( 2 - 3 x ) ^{3}}, at x = 2

\int_{1}^{3} 3 x^{2} d x

x y^{^{'}} + 3 y = \frac{( 2 e ^{- 4 x} )}{x ^{2}}

What is the solution for (d^2)/(dx^2)y=sin(x) ?
The solution for (d^2)/(dx^2)y=sin(x) is y=-sin(x)+c_{1}x+c_{2}