What is the derivative of (3x^2+1^2) ?

The derivative of (3x^2+1^2) is 12x(3x^2+1)

What is the first derivative of (3x^2+1^2) ?

The first derivative of (3x^2+1^2) is 12x(3x^2+1)

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\frac{d}{d x} ((3 x^{2} + 1)^{2})

12 x (3 x^{2} + 1)

Solution steps

\frac{d}{d x} ((3 x^{2} + 1)^{2})

Apply the chain rule:

2 (3 x^{2} + 1) \frac{d}{d x} (3 x^{2} + 1)

= 2 (3 x^{2} + 1) \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= 2 (3 x^{2} + 1) \cdot 6 x

Simplify

= 12 x (3 x^{2} + 1)

\int x (sec (2 y) + 2) d x

\frac{d}{d x} (\frac{1}{7})

\int cos (x y) d x

x \to - 1 - lim (\frac{x - 1}{x ^{3} - 1})

\frac{\partial}{\partial x} (x^{2} sin^{2} (yz))

What is the derivative of (3x^2+1^2) ?
The derivative of (3x^2+1^2) is 12x(3x^2+1)
What is the first derivative of (3x^2+1^2) ?
The first derivative of (3x^2+1^2) is 12x(3x^2+1)