What is (\partial)/(\partial x)(x^2sin^2(yz)) ?

The answer to (\partial)/(\partial x)(x^2sin^2(yz)) is 2xsin^2(yz)

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(\partial)/(\partial x)(x^2sin^2(yz))

\frac{\partial}{\partial x} (x^{2} sin^{2} (yz))

2 x sin^{2} (yz)

Solution steps

\frac{\partial}{\partial x} (x^{2} sin^{2} (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin^{2} (yz) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sin^{2} (yz) \cdot 2 x^{2 - 1}

Simplify

= 2 x sin^{2} (yz)

\frac{d}{d x} ((ln (x + 1))^{3})

x \to 3 lim (x + 7)

\int 3 arccos (\frac{x}{2}) d x

\frac{\partial}{\partial x} (x^{2} + x y)

f (x) = 7 x^{4} + 5 x - 3, (1, 9)

What is (\partial)/(\partial x)(x^2sin^2(yz)) ?
The answer to (\partial)/(\partial x)(x^2sin^2(yz)) is 2xsin^2(yz)