What is the derivative of 2x^2+3x+4 ?

The derivative of 2x^2+3x+4 is 4x+3

What is the first derivative of 2x^2+3x+4 ?

The first derivative of 2x^2+3x+4 is 4x+3

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\frac{d}{d x} (2 x^{2} + 3 x + 4)

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 4 x + 3 + 0

Simplify

= 4 x + 3

\frac{d y}{d x} = sin (y) cos (x)

f (x) = x^{2} + 7, (4, 23)

\int 2 y + 4 e^{y} d y

z \to 3 lim (2 z^{3})

f (x) = x (x - 2)

What is the derivative of 2x^2+3x+4 ?
The derivative of 2x^2+3x+4 is 4x+3
What is the first derivative of 2x^2+3x+4 ?
The first derivative of 2x^2+3x+4 is 4x+3