What is the tangent of f(x)=sin(x) ?

The tangent of f(x)=sin(x) is y=cos(a_{0})x+sin(a_{0})-cos(a_{0})a_{0}

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tangent of f(x)=sin(x)

tangent of

f (x) = sin (x)

y = cos (a_{0}) x + sin (a_{0}) - cos (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, sin (a_{0}))

Find the slope of

f (x) = sin (x) : \frac{df ( x )}{d x} = cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = cos (a_{0})

Find the line with slope m=

cos (a_{0})

and passing through

(a_{0}, sin (a_{0})) : y = cos (a_{0}) x + sin (a_{0}) - cos (a_{0}) a_{0}

y = cos (a_{0}) x + sin (a_{0}) - cos (a_{0}) a_{0}

(\frac{1}{x + 2})^{^{'}}

\int_{- 1}^{4} 3 y - (y^{2} - 4) d y

x \to 0 lim (\frac{( 1 + x ) ^{2} + 1}{x})

y = 12 x, y = 4 x^{2}

\int \frac{cos ( x )}{sin ( x ) ( sin ( x ) - 1 )} d x

What is the tangent of f(x)=sin(x) ?
The tangent of f(x)=sin(x) is y=cos(a_{0})x+sin(a_{0})-cos(a_{0})a_{0}