What is the derivative of f(x)=(1+x)/(e^x) ?

The derivative of f(x)=(1+x)/(e^x) is -x/(e^x)

What is the first derivative of f(x)=(1+x)/(e^x) ?

The first derivative of f(x)=(1+x)/(e^x) is -x/(e^x)

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derivative of

f (x) = \frac{1 + x}{e ^{x}}

- \frac{x}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{1 + x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + x ) e ^{x} - \frac{d}{d x} ( e ^{x} ) ( 1 + x )}{( e ^{x} ) ^{2}}

\frac{d}{d x} (1 + x) = 1

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{1 \cdot e ^{x} - e ^{x} ( 1 + x )}{( e ^{x} ) ^{2}}

Simplify

\frac{1 \cdot e ^{x} - e ^{x} ( 1 + x )}{( e ^{x} ) ^{2}} : - \frac{x}{e ^{x}}

= - \frac{x}{e ^{x}}

\frac{d}{d x} (\frac{2 ab}{( a - b x ) ^{2}})

\frac{\partial}{\partial y} (2 x - 2 y)

\int t (t^{6} + t - 4) d t

f (x) = 6 + x^{2}

y^{^{''}} + y = sec (x)

What is the derivative of f(x)=(1+x)/(e^x) ?
The derivative of f(x)=(1+x)/(e^x) is -x/(e^x)
What is the first derivative of f(x)=(1+x)/(e^x) ?
The first derivative of f(x)=(1+x)/(e^x) is -x/(e^x)