What is (\partial)/(\partial y)(2x-2y) ?

The answer to (\partial)/(\partial y)(2x-2y) is -2

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(\partial)/(\partial y)(2x-2y)

\frac{\partial}{\partial y} (2 x - 2 y)

- 2

Solution steps

\frac{\partial}{\partial y} (2 x - 2 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (2 y) = 2

= 0 - 2

Simplify

= - 2

\int t (t^{6} + t - 4) d t

f (x) = 6 + x^{2}

y^{^{''}} + y = sec (x)

x \to 0 lim (\frac{2}{sin ( 7 x )})

n = 1 \sum \infty n^{\frac{1}{n}}

What is (\partial)/(\partial y)(2x-2y) ?
The answer to (\partial)/(\partial y)(2x-2y) is -2