What is the tangent of f(x)=3e^x+2x,\at x=0 ?

The tangent of f(x)=3e^x+2x,\at x=0 is y=5x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=3e^x+2x,\at x=0

tangent of

f (x) = 3 e^{x} + 2 x, at x = 0

y = 5 x + 3

Solution steps

Find the tangent point:

(0, 3)

Find the slope of

f (x) = 3 e^{x} + 2 x : \frac{df ( x )}{d x} = 3 e^{x} + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(0, 3) : y = 5 x + 3

y = 5 x + 3

\int \frac{2 x}{( 2 - x ) ^{6}} d x

9 π x^{2}

\int \frac{1}{1 + 81 x ^{2}} d x

(2 x sin (y) cos (y)) y^{^{'}} = 4 x^{2} + sin^{2} (y)

\frac{d}{d x} (tan (e^{6 x}) + e^{t a n (6 x)})

What is the tangent of f(x)=3e^x+2x,\at x=0 ?
The tangent of f(x)=3e^x+2x,\at x=0 is y=5x+3