en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x=y^2-2,(-2,2)

Solution

area

x = y^{2} - 2, (- 2, 2)

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Isolate

y

for

x = y^{2} - 2 : y = x + 2, y = - x + 2

Apply the area formula:

\int_{- 2}^{2} 2 x + 2 d x

Solve

\int_{- 2}^{2} 2 x + 2 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

y'=y(1-0.0008y)

y^{'} = y (1 - 0.0008 y)

derivative of f(x)=(2x)/(x-1)derivative of

f (x) = \frac{2 x}{x - 1}

integral of sin(x)*cos^2(x)

\int sin (x) \cdot cos^{2} (x) d x

derivative of e^{4x^{2+1}}

\frac{d}{d x} (e^{4 x^{2 + 1}})

limit as x approaches 0+of 2/x-3/2

x \to 0 + lim (\frac{2}{x} - \frac{3}{2})

Frequently Asked Questions (FAQ)

What is area x=y^2-2,(-2,2) ?
The answer to area x=y^2-2,(-2,2) is 32/3