What is the derivative of f(r)=pir^2 ?

The derivative of f(r)=pir^2 is 2pir

What is the first derivative of f(r)=pir^2 ?

The first derivative of f(r)=pir^2 is 2pir

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derivative of

f (r) = π r^{2}

2 π r

Solution steps

\frac{d}{d r} (π r^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= π \frac{d}{d r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= π 2 r^{2 - 1}

Simplify

= 2 π r

\frac{d}{d x} (e^{c x})

\int_{- 1}^{3} (x^{2} - 3) d x

2 cos (2 x) + 2 sin (2 x) + 4 x

\int (2 + x) d x

\frac{d}{d x} (\frac{- 2}{3 x + 7})

What is the derivative of f(r)=pir^2 ?
The derivative of f(r)=pir^2 is 2pir
What is the first derivative of f(r)=pir^2 ?
The first derivative of f(r)=pir^2 is 2pir