What is the derivative of (x+1/(e^x)) ?

The derivative of (x+1/(e^x)) is -x/(e^x)

What is the first derivative of (x+1/(e^x)) ?

The first derivative of (x+1/(e^x)) is -x/(e^x)

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\frac{d}{d x} (\frac{x + 1}{e ^{x}})

- \frac{x}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) e ^{x} - \frac{d}{d x} ( e ^{x} ) ( x + 1 )}{( e ^{x} ) ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{1 \cdot e ^{x} - e ^{x} ( x + 1 )}{( e ^{x} ) ^{2}}

Simplify

\frac{1 \cdot e ^{x} - e ^{x} ( x + 1 )}{( e ^{x} ) ^{2}} : - \frac{x}{e ^{x}}

= - \frac{x}{e ^{x}}

f (x) = \frac{x ^{2} + 2 x - 5}{( x + 1 ) ^{2}}

t = \frac{1 - y ^{2}}{y ^{^{'}}}

y = 8

f (x) = \frac{1}{x ^{4}}, at x = - 3

n = 1 \sum \infty (\frac{5}{6})^{n} n

What is the derivative of (x+1/(e^x)) ?
The derivative of (x+1/(e^x)) is -x/(e^x)
What is the first derivative of (x+1/(e^x)) ?
The first derivative of (x+1/(e^x)) is -x/(e^x)