What is the limit as x approaches infinity of 2^{-x} ?

The limit as x approaches infinity of 2^{-x} is 0

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limit as x approaches infinity of 2^{-x}

x \to \infty lim (2^{- x})

0

Solution steps

x \to \infty lim (2^{- x})

Apply exponent rules

= x \to \infty lim (e^{- x l n (2)})

Apply the Limit Chain Rule:

0

= 0

\int 5 sin^{4} (x) d x

y = x (2 x + 1)^{3}

\int 10 - t d t

y = x^{- 2}

\frac{s + 1}{s ^{2} ( s - 1 )}

What is the limit as x approaches infinity of 2^{-x} ?
The limit as x approaches infinity of 2^{-x} is 0