What is the derivative of ln(x+6) ?

The derivative of ln(x+6) is 1/(x+6)

What is the first derivative of ln(x+6) ?

The first derivative of ln(x+6) is 1/(x+6)

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derivative of

ln (x + 6)

\frac{1}{x + 6}

Solution steps

\frac{d}{d x} (ln (x + 6))

Apply the chain rule:

\frac{1}{x + 6} \frac{d}{d x} (x + 6)

= \frac{1}{x + 6} \frac{d}{d x} (x + 6)

\frac{d}{d x} (x + 6) = 1

= \frac{1}{x + 6} \cdot 1

Simplify

= \frac{1}{x + 6}

y^{^{'}} = 9 y^{2} + x y^{2}

\frac{d}{d x} (\frac{2 x}{x - 1})

y = e^{4} x^{2} + 18

f (x) = (\frac{8 x + 7}{9 x ^{2} + 6})

y = cos (x), y = sin (x)

What is the derivative of ln(x+6) ?
The derivative of ln(x+6) is 1/(x+6)
What is the first derivative of ln(x+6) ?
The first derivative of ln(x+6) is 1/(x+6)