What is the integral from-infinity to 0 of 1/(7-3x) ?

The integral from-infinity to 0 of 1/(7-3x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of 1/(7-3x)

\int_{- \infty}^{0} \frac{1}{7 - 3 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 3 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 3 x} d x = - \frac{1}{3} ln ∣ 7 - 3 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 3 x} d x =

diverges

= diverges

\int \frac{20}{( 100 x ^{2} + 1 ) ^{2}} d x

\frac{d}{d t} (sin (t) - t cos (t))

9 x^{2} y^{2} + x^{\frac{3}{2}} \frac{d y}{d x} = y^{2}

\frac{x}{x ^{- 1} + 7}

\int \frac{w ^{3}}{w + 1} d w

What is the integral from-infinity to 0 of 1/(7-3x) ?
The integral from-infinity to 0 of 1/(7-3x) is diverges