What is the derivative of (x-4/3) ?

The derivative of (x-4/3) is 1/3

What is the first derivative of (x-4/3) ?

The first derivative of (x-4/3) is 1/3

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\frac{d}{d x} (\frac{x - 4}{3})

\frac{1}{3}

Solution steps

\frac{d}{d x} (\frac{x - 4}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d x}{d x} - \frac{d}{d x} (4))

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= \frac{1}{3} (1 - 0)

Simplify

= \frac{1}{3}

y = 4 x^{3} e^{- x}

\int (- \frac{x ^{3}}{3} - x^{2} + \frac{4}{3}) d x

f (x) = e^{x}, x = 0

\frac{d}{d x} (A e^{3 x})

f (x) = 5 x^{3}, - 10, 15, at x = 0

What is the derivative of (x-4/3) ?
The derivative of (x-4/3) is 1/3
What is the first derivative of (x-4/3) ?
The first derivative of (x-4/3) is 1/3