What is the tangent of f(x)=5x^3,-10,15,\at x=0 ?

The tangent of f(x)=5x^3,-10,15,\at x=0 is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=5x^3,-10,15,\at x=0

tangent of

f (x) = 5 x^{3}, - 10, 15, at x = 0

y = 0

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = 5 x^{3} : \frac{df ( x )}{d x} = 15 x^{2}

Compute the slope of

f (x) = 5 x^{3}

x = 0 : m = 0

Find the line with slope m=

0

and passing through

(0, 0) : y = 0

y = 0

\frac{\partial}{\partial x} (1 - x^{2} - y^{2})

\int_{- 2}^{0} \frac{y}{2} + y + 3 d y

\frac{d}{d x} ((x^{2} + x)^{4})

y = 4 x^{3} - 10 x^{2}

y^{^{''}} + 4 y = t e^{t}

What is the tangent of f(x)=5x^3,-10,15,\at x=0 ?
The tangent of f(x)=5x^3,-10,15,\at x=0 is y=0