What is (\partial)/(\partial x)(sqrt(1-x^2-y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(1-x^2-y^2)) is -x/(sqrt(1-x^2-y^2))

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(\partial)/(\partial x)(sqrt(1-x^2-y^2))

\frac{\partial}{\partial x} (1 - x^{2} - y^{2})

- \frac{x}{1 - x ^{2} - y ^{2}}

Solution steps

\frac{\partial}{\partial x} (1 - x^{2} - y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 1 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (1 - x^{2} - y^{2})

= \frac{1}{2 1 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (1 - x^{2} - y^{2})

\frac{\partial}{\partial x} (1 - x^{2} - y^{2}) = - 2 x

= \frac{1}{2 1 - x ^{2} - y ^{2}} (- 2 x)

Simplify

\frac{1}{2 1 - x ^{2} - y ^{2}} (- 2 x) : - \frac{x}{1 - x ^{2} - y ^{2}}

= - \frac{x}{1 - x ^{2} - y ^{2}}

\int_{- 2}^{0} \frac{y}{2} + y + 3 d y

\frac{d}{d x} ((x^{2} + x)^{4})

y = 4 x^{3} - 10 x^{2}

y^{^{''}} + 4 y = t e^{t}

x \to 2 - lim (\frac{4 x + 1}{x - 2})

What is (\partial)/(\partial x)(sqrt(1-x^2-y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(1-x^2-y^2)) is -x/(sqrt(1-x^2-y^2))