What is the limit as u approaches 0 of ln((u+1)/u) ?

The limit as u approaches 0 of ln((u+1)/u) is Does not exist

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limit as u approaches 0 of ln((u+1)/u)

u \to 0 lim (ln (\frac{u + 1}{u}))

Does not exist

Solution steps

u \to 0 lim (ln (\frac{u + 1}{u}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

u \to 0 + lim (ln (\frac{u + 1}{u})) = \infty

u \to 0 - lim (ln (\frac{u + 1}{u})) =

Does not exist

= Does not exist

y = - x^{3} + 2 x^{2} - 4, at x = - 1

(- 4.3) (5.3)

n = 1 \sum \infty \frac{5}{3 ^{n} + 1}

n = 0 \sum \infty (2 n - 3) (4 x)^{n}

f (t) = 1.7 e^{0.76 t}

What is the limit as u approaches 0 of ln((u+1)/u) ?
The limit as u approaches 0 of ln((u+1)/u) is Does not exist