What is the derivative of y=x^{2/3}-x ?

The derivative of y=x^{2/3}-x is 2/(3x^{1/3)}-1

What is the first derivative of y=x^{2/3}-x ?

The first derivative of y=x^{2/3}-x is 2/(3x^{1/3)}-1

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derivative of

y = x^{\frac{2}{3}} - x

\frac{2}{3 x ^{\frac{1}{3}}} - 1

Solution steps

\frac{d}{d x} (x^{\frac{2}{3}} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{2}{3}}) - \frac{d x}{d x}

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

\frac{d x}{d x} = 1

= \frac{2}{3 x ^{\frac{1}{3}}} - 1

\frac{d}{d x} (x^{2} - 2 x^{2})

\int t sinh (m t) d t

f (x) = \frac{3}{x + 1}, at x = - 2

\frac{d y}{d t} = - 0.4 y + 6.2 e^{- 0.73 t}

\int e^{x} (cos (x)) d x

What is the derivative of y=x^{2/3}-x ?
The derivative of y=x^{2/3}-x is 2/(3x^{1/3)}-1
What is the first derivative of y=x^{2/3}-x ?
The first derivative of y=x^{2/3}-x is 2/(3x^{1/3)}-1