What is the derivative of y= x/5-5/x ?

The derivative of y= x/5-5/x is 1/5+5/(x^2)

What is the first derivative of y= x/5-5/x ?

The first derivative of y= x/5-5/x is 1/5+5/(x^2)

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derivative of

y = \frac{x}{5} - \frac{5}{x}

\frac{1}{5} + \frac{5}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{5} - \frac{5}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{5}) - \frac{d}{d x} (\frac{5}{x})

\frac{d}{d x} (\frac{x}{5}) = \frac{1}{5}

\frac{d}{d x} (\frac{5}{x}) = - \frac{5}{x ^{2}}

= \frac{1}{5} - (- \frac{5}{x ^{2}})

Simplify

= \frac{1}{5} + \frac{5}{x ^{2}}

x \to 1 lim (\frac{x}{ln ( 1 + x )})

y = x + e^{x} - \frac{1}{x}, at x = 1

(- 3 x^{2} - 3)^{4}

x \to 2 lim (x^{2} + x + 2)

\frac{\partial}{\partial x} (x^{2} y z^{2} + sin (yz))

What is the derivative of y= x/5-5/x ?
The derivative of y= x/5-5/x is 1/5+5/(x^2)
What is the first derivative of y= x/5-5/x ?
The first derivative of y= x/5-5/x is 1/5+5/(x^2)