What is the limit as x approaches 1 of x/(ln(1+x)) ?

The limit as x approaches 1 of x/(ln(1+x)) is 1/(ln(2))

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limit as x approaches 1 of x/(ln(1+x))

x \to 1 lim (\frac{x}{ln ( 1 + x )})

\frac{1}{ln ( 2 )}

Decimal

1.44269 \dots

Solution steps

x \to 1 lim (\frac{x}{ln ( 1 + x )})

Plug in the value

x = 1

= \frac{1}{ln ( 1 + 1 )}

Simplify

= \frac{1}{ln ( 2 )}

y = x + e^{x} - \frac{1}{x}, at x = 1

(- 3 x^{2} - 3)^{4}

x \to 2 lim (x^{2} + x + 2)

\frac{\partial}{\partial x} (x^{2} y z^{2} + sin (yz))

\frac{d}{d x} (2 + sin (3 x))

What is the limit as x approaches 1 of x/(ln(1+x)) ?
The limit as x approaches 1 of x/(ln(1+x)) is 1/(ln(2))