What is area y=xsqrt(4-x^2),(2,-2) ?

The answer to area y=xsqrt(4-x^2),(2,-2) is 16/3

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area y=xsqrt(4-x^2),(2,-2)

area

y = x 4 - x^{2}, (2, - 2)

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} ∣ x ∣ 4 - x^{2} d x

Solve

\int_{- 2}^{2} ∣ x ∣ 4 - x^{2} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

\frac{d}{d x} ((cos (4 x))^{x})

\frac{d}{d x} (sin^{3} (x^{3}))

(\frac{x + 2}{x - 2})^{5}

f (1) = 2 x^{3}

What is area y=xsqrt(4-x^2),(2,-2) ?
The answer to area y=xsqrt(4-x^2),(2,-2) is 16/3