What is the derivative of f(1)=2x^3 ?

The derivative of f(1)=2x^3 is 6x^2

What is the first derivative of f(1)=2x^3 ?

The first derivative of f(1)=2x^3 is 6x^2

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derivative of

f (1) = 2 x^{3}

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2}

\frac{1}{s ^{3} ( s + 1 )}

\int 0.06 x - 0.6 - \frac{7700}{x ^{2}} d x

\int_{- 1}^{1} 1 2^{x} d x

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 1})

y^{^{''}} + (8) y = 0

What is the derivative of f(1)=2x^3 ?
The derivative of f(1)=2x^3 is 6x^2
What is the first derivative of f(1)=2x^3 ?
The first derivative of f(1)=2x^3 is 6x^2