What is the solution for x^{''}+9x=0,x(0)=0.7,x^'(0)=0.4 ?

The solution for x^{''}+9x=0,x(0)=0.7,x^'(0)=0.4 is x=0.7cos(3t)+0.13333…sin(3t)

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x^{''}+9x=0,x(0)=0.7,x^'(0)=0.4

x^{^{''}} + 9 x = 0, x (0) = 0.7, x^{^{'}} (0) = 0.4

x = 0.7 cos (3 t) + 0.13333 \dots sin (3 t)

Solution steps

x^{''} (t) + 9 x = 0

Solve linear ODE:

x = 0.7 cos (3 t) + 0.13333 \dots sin (3 t)

x = 0.7 cos (3 t) + 0.13333 \dots sin (3 t)

x \to 2 lim (- x^{2})

\int 7 x 1 - x^{4} d x

\frac{d}{d x} (\frac{1}{2 x - 5})

f (2) = 4 lo g_{6} (x)

\frac{d}{d x} (2^{x} + 3)

What is the solution for x^{''}+9x=0,x(0)=0.7,x^'(0)=0.4 ?
The solution for x^{''}+9x=0,x(0)=0.7,x^'(0)=0.4 is x=0.7cos(3t)+0.13333…sin(3t)