What is laplacetransform e^{-2t}cos(t) ?

The answer to laplacetransform e^{-2t}cos(t) is (s+2)/((s+2)^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e^{-2t}cos(t)

laplace transform

e^{- 2 t} cos (t)

\frac{s + 2}{( s + 2 ) ^{2} + 1}

Solution steps

L {e^{- 2 t} cos (t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{- 2 t} cos (t) : f (t) = cos (t), a = - 2

= L {cos (t)} (s + 2)

L {cos (t)} : \frac{s}{s ^{2} + 1}

= \frac{( s + 2 )}{( s + 2 ) ^{2} + 1}

= \frac{s + 2}{( s + 2 ) ^{2} + 1}

\int \frac{7}{x + 3} d x

\int (sin (x))^{5} cos (x) d x

f (x) = 14 x^{\frac{1}{7}}

\frac{d}{d x} (arccsc (- 9 x^{2}))

8 x e^{x}

What is laplacetransform e^{-2t}cos(t) ?
The answer to laplacetransform e^{-2t}cos(t) is (s+2)/((s+2)^2+1)