What is the solution for (3dy)/(dx)+15y=90,y(0)=0 ?

The solution for (3dy)/(dx)+15y=90,y(0)=0 is y=-e^{-5x-c_{1}}+6

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(3dy)/(dx)+15y=90,y(0)=0

\frac{3 d y}{d x} + 15 y = 90, y (0) = 0

y = - e^{- 5 x - c_{1}} + 6

Solution steps

\frac{3 d y}{d x} + 15 y = 90

Solve separable ODE:

y = - e^{- 5 x - c_{1}} + 6

y = - e^{- 5 x - c_{1}} + 6

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\frac{d}{d x} (ln (\frac{x}{x}))

\frac{d}{d t} (a cos^{3} (t))

f (x) = x^{2} + 21, at x = 2

\frac{\partial}{\partial z} (x^{2} + y^{2})

What is the solution for (3dy)/(dx)+15y=90,y(0)=0 ?
The solution for (3dy)/(dx)+15y=90,y(0)=0 is y=-e^{-5x-c_{1}}+6