What is the d/(dt)(acos^3(t)) ?

The d/(dt)(acos^3(t)) is -3acos^2(t)sin(t)

What is the first d/(dt)(acos^3(t)) ?

The first d/(dt)(acos^3(t)) is -3acos^2(t)sin(t)

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\frac{d}{d t} (a cos^{3} (t))

- 3 a cos^{2} (t) sin (t)

Solution steps

\frac{d}{d t} (a cos^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d t} (cos^{3} (t))

Apply the chain rule:

3 (cos (t))^{2} \frac{d}{d t} (cos (t))

= 3 (cos (t))^{2} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= a \cdot 3 (cos (t))^{2} (- sin (t))

Simplify

= - 3 a cos^{2} (t) sin (t)

f (x) = x^{2} + 21, at x = 2

\frac{\partial}{\partial z} (x^{2} + y^{2})

\frac{d y}{d x} = \frac{- 2 x}{y}

y = x + x

(x + y e^{(\frac{y}{x})}) d x - (x e^{\frac{y}{x}}) d y = 0

What is the d/(dt)(acos^3(t)) ?
The d/(dt)(acos^3(t)) is -3acos^2(t)sin(t)
What is the first d/(dt)(acos^3(t)) ?
The first d/(dt)(acos^3(t)) is -3acos^2(t)sin(t)