What is (\partial)/(\partial x)(2x^3y+cos(x^2)) ?

The answer to (\partial)/(\partial x)(2x^3y+cos(x^2)) is 6yx^2-sin(x^2)*2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^3y+cos(x^2))

\frac{\partial}{\partial x} (2 x^{3} y + cos (x^{2}))

6 y x^{2} - sin (x^{2}) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (2 x^{3} y + cos (x^{2}))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{3} y) + \frac{\partial}{\partial x} (cos (x^{2}))

\frac{\partial}{\partial x} (2 x^{3} y) = 6 y x^{2}

\frac{\partial}{\partial x} (cos (x^{2})) = - sin (x^{2}) \cdot 2 x

= 6 y x^{2} - sin (x^{2}) \cdot 2 x

\frac{d}{d x} (\frac{x + 2}{x - 2})

\int (\frac{9 + x + x}{x}) d x

\int (2 x + 5) e^{x} d x

y^{^{'}} - 2 x y = e^{x^{2}}

\int (2 x^{10} + 4 x^{9} + x^{8} + 10) d x

What is (\partial)/(\partial x)(2x^3y+cos(x^2)) ?
The answer to (\partial)/(\partial x)(2x^3y+cos(x^2)) is 6yx^2-sin(x^2)*2x