What is the integral of (2x^{10}+4x^9+x^8+10) ?

The integral of (2x^{10}+4x^9+x^8+10) is (2x^{11}}{11}+\frac{2x^{10})/5+(x^9)/9+10x+C

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integral of (2x^{10}+4x^9+x^8+10)

\int (2 x^{10} + 4 x^{9} + x^{8} + 10) d x

\frac{2 x ^{11}}{11} + \frac{2 x ^{10}}{5} + \frac{x ^{9}}{9} + 10 x + C

Solution steps

\int 2 x^{10} + 4 x^{9} + x^{8} + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{10} d x + \int 4 x^{9} d x + \int x^{8} d x + \int 10 d x

\int 2 x^{10} d x = \frac{2 x ^{11}}{11}

\int 4 x^{9} d x = \frac{2 x ^{10}}{5}

\int x^{8} d x = \frac{x ^{9}}{9}

\int 10 d x = 10 x

= \frac{2 x ^{11}}{11} + \frac{2 x ^{10}}{5} + \frac{x ^{9}}{9} + 10 x

Add a constant to the solution

= \frac{2 x ^{11}}{11} + \frac{2 x ^{10}}{5} + \frac{x ^{9}}{9} + 10 x + C

\int x^{2} (x^{2} - 6 x + 9) d x

\frac{d}{d x} (10 x^{2} - 5 x + 9)

\int (e^{x} + 1)^{3} d x

\int (3 x^{2} - 6 x + \frac{9}{x} + 4 e^{x}) d x

y^{^{'}} = 0.05 y - 12 \cdot 4000

What is the integral of (2x^{10}+4x^9+x^8+10) ?
The integral of (2x^{10}+4x^9+x^8+10) is (2x^{11}}{11}+\frac{2x^{10})/5+(x^9)/9+10x+C