What is the integral of 7cos(x)+8sin(x) ?

The integral of 7cos(x)+8sin(x) is 7sin(x)-8cos(x)+C

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integral of 7cos(x)+8sin(x)

\int 7 cos (x) + 8 sin (x) d x

7 sin (x) - 8 cos (x) + C

Solution steps

\int 7 cos (x) + 8 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 cos (x) d x + \int 8 sin (x) d x

\int 7 cos (x) d x = 7 sin (x)

\int 8 sin (x) d x = - 8 cos (x)

= 7 sin (x) - 8 cos (x)

Add a constant to the solution

= 7 sin (x) - 8 cos (x) + C

\int \frac{1}{x 4 - 9 ln ^{2} ( x )} d x

f (x) = sin (2 x), at x = - \frac{π}{3}

\frac{( x ^{2} - 1 ) ^{3}}{x ^{2} + 2}

\int (- sec^{2} (x)) d x

h (x) = (ln (x)) (3 x^{3})

What is the integral of 7cos(x)+8sin(x) ?
The integral of 7cos(x)+8sin(x) is 7sin(x)-8cos(x)+C