What is the integral of (-sec^2(x)) ?

The integral of (-sec^2(x)) is -tan(x)+C

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integral of (-sec^2(x))

\int (- sec^{2} (x)) d x

- tan (x) + C

Solution steps

\int - sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - tan (x)

Add a constant to the solution

= - tan (x) + C

h (x) = (ln (x)) (3 x^{3})

\int e^{4 x + 1} d x

y^{^{''}} + 20 y^{^{'}} + 500 y = 12

\int \frac{1}{cos ^{2} ( x )} d x

x \to 2 lim (\frac{x ^{3} + 7 x + 6}{x ^{3} + x ^{2} - 4 x - 4})