What is (\partial)/(\partial y)(6-3x-2y) ?

The answer to (\partial)/(\partial y)(6-3x-2y) is -2

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(\partial)/(\partial y)(6-3x-2y)

\frac{\partial}{\partial y} (6 - 3 x - 2 y)

- 2

Solution steps

\frac{\partial}{\partial y} (6 - 3 x - 2 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (6) - \frac{\partial}{\partial y} (3 x) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (6) = 0

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (2 y) = 2

= 0 - 0 - 2

Simplify

= - 2

\int_{- \infty}^{- 1} e^{- 34 t} d t

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}

\frac{\partial}{\partial x} (k v (1 - e^{(- \frac{t}{k})}))

\int_{0}^{3} x d x

x^{3} y^{^{'}} + 2 x^{2} y = 2 cos (3 x) y^{- \frac{1}{2}}

What is (\partial)/(\partial y)(6-3x-2y) ?
The answer to (\partial)/(\partial y)(6-3x-2y) is -2