What is the integral from 0 to 1 of-x^2 ?

The integral from 0 to 1 of-x^2 is -1/3

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integral from 0 to 1 of-x^2

\int_{0}^{1} - x^{2} d x

- \frac{1}{3}

Decimal Notation

- 0.33333 \dots

Solution steps

\int_{0}^{1} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= - [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= - \frac{1}{3}

\int \frac{sin ( x )}{x ^{2} + 1} d x

2 e^{- 3 t}

\int 17 x^{2} sin (π x) d x

\int - x + 1 d x

x \to 1 lim (a x^{2} + b x + 1)

What is the integral from 0 to 1 of-x^2 ?
The integral from 0 to 1 of-x^2 is -1/3