What is the limit as x approaches 1 of ax^2+bx+1 ?

The limit as x approaches 1 of ax^2+bx+1 is a+b+1

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limit as x approaches 1 of ax^2+bx+1

x \to 1 lim (a x^{2} + b x + 1)

a + b + 1

Solution steps

x \to 1 lim (a x^{2} + b x + 1)

Plug in the value

x = 1

= a \cdot 1^{2} + b \cdot 1 + 1

Simplify

= a + b + 1

n = 0 \sum \infty \frac{2}{n ( n + 1 )}

x \to 0 lim (+ (\frac{1}{3} + \frac{5}{3 x}))

f (x) = - 2 t^{2} + 3 t - 6

\frac{d}{d x} (\frac{d y}{d x}) + y = 1

\frac{3 s + 2}{s ^{2} + 2 s + 10}

What is the limit as x approaches 1 of ax^2+bx+1 ?
The limit as x approaches 1 of ax^2+bx+1 is a+b+1