What is the limit as x approaches 0 of+(1/3+5/(3x)) ?

The limit as x approaches 0 of+(1/3+5/(3x)) is diverges

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limit as x approaches 0 of+(1/3+5/(3x))

x \to 0 lim (+ (\frac{1}{3} + \frac{5}{3 x}))

diverges

Solution steps

x \to 0 lim (\frac{1}{3} + \frac{5}{3 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{3} + \frac{5}{3 x}) = \infty

x \to 0 - lim (\frac{1}{3} + \frac{5}{3 x}) = - \infty

= diverges

f (x) = - 2 t^{2} + 3 t - 6

\frac{d}{d x} (\frac{d y}{d x}) + y = 1

\frac{3 s + 2}{s ^{2} + 2 s + 10}

2 a x + b

x \to 5 lim (\frac{( x + 1 )}{x - 5})

What is the limit as x approaches 0 of+(1/3+5/(3x)) ?
The limit as x approaches 0 of+(1/3+5/(3x)) is diverges