What is the derivative of 9sin(2x) ?

The derivative of 9sin(2x) is 18cos(2x)

What is the first derivative of 9sin(2x) ?

The first derivative of 9sin(2x) is 18cos(2x)

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derivative of

9 sin (2 x)

18 cos (2 x)

Solution steps

\frac{d}{d x} (9 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 9 cos (2 x) \cdot 2

Simplify

= 18 cos (2 x)

f (x) = \frac{x}{4 + x ^{2}}

(4^{x})^{^{'}}

n = 1 \sum \infty ln (\frac{n}{n + 1})

y^{^{''}} - 6 y^{^{'}} + 11 y = 0

n = 0 \sum \infty \frac{1}{n + 11}

What is the derivative of 9sin(2x) ?
The derivative of 9sin(2x) is 18cos(2x)
What is the first derivative of 9sin(2x) ?
The first derivative of 9sin(2x) is 18cos(2x)