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Popular >

integral from 0 to 5 of |9-3t|

Solution

\int_{0}^{5} ∣ 9 - 3 t ∣ d t

Solution

\frac{39}{2}

+1

Decimal Notation

19.5

Solution steps

\int_{0}^{5} ∣ 9 - 3 t ∣ d t

Eliminate Absolutes

= \int_{0}^{3} 9 - 3 t d t + \int_{3}^{5} - 9 + 3 t d t

\int_{0}^{3} 9 - 3 t d t = \frac{27}{2}

\int_{3}^{5} - 9 + 3 t d t = 6

= \frac{27}{2} + 6

Simplify

\frac{27}{2} + 6 : \frac{39}{2}

= \frac{39}{2}

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of |9-3t| ?
The integral from 0 to 5 of |9-3t| is 39/2