What is area y(x+4)=1,x=0,y=0,x=4 ?

The answer to area y(x+4)=1,x=0,y=0,x=4 is ln(2)

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area y(x+4)=1,x=0,y=0,x=4

area

y (x + 4) = 1, x = 0, y = 0, x = 4

ln (2)

Decimal Notation

0.69314 \dots

Solution steps

Isolate

y

for

y (x + 4) = 1 : y = \frac{1}{x + 4}; x \neq = - 4

Apply the area formula:

\int_{0}^{4} \frac{1}{∣ x + 4 ∣} d x

Solve

\int_{0}^{4} \frac{1}{∣ x + 4 ∣} d x : ln (2)

The area is:

= ln (2)

\int (ln (16 x))^{2} d x

\int (- 6 x^{6} - 2 x^{3} - 4) d x

y = x^{2} - 39, y = 9 - 2 x

\frac{\partial}{\partial y} (12 x y)

10 sin (t)

What is area y(x+4)=1,x=0,y=0,x=4 ?
The answer to area y(x+4)=1,x=0,y=0,x=4 is ln(2)