What is the integral from 0 to 1 of (58)/(4y-1) ?

The integral from 0 to 1 of (58)/(4y-1) is diverges

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integral from 0 to 1 of (58)/(4y-1)

\int_{0}^{1} \frac{58}{4 y - 1} d y

diverges

Solution steps

\int_{0}^{1} \frac{58}{4 y - 1} d y

Find undefined (singularity) points:

y = \frac{1}{4}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{1}{4}} \frac{58}{4 y - 1} d y + \int_{\frac{1}{4}}^{1} \frac{58}{4 y - 1} d y

\int_{0}^{\frac{1}{4}} \frac{58}{4 y - 1} d y =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{d y}{d x} = \frac{x y}{2}

\int \frac{2 x ^{3} + 11 x + 8}{x ^{3} + 4 x ^{2} + 4 x} d x

y^{^{''''}} + 17 y^{^{''}} + 16 y = 0

w \to 0 lim (\frac{a - w ^{2} + a ^{2}}{b - w ^{2} + b ^{2}})

2 x^{2} + x - 3, at x = - 1

What is the integral from 0 to 1 of (58)/(4y-1) ?
The integral from 0 to 1 of (58)/(4y-1) is diverges