What is the integral of 1/(xsqrt(x^2-2)) ?

The integral of 1/(xsqrt(x^2-2)) is 1/(sqrt(2))arcsec(1/(sqrt(2))x)+C

Popular >

integral of 1/(xsqrt(x^2-2))

\int \frac{1}{x x ^{2} - 2} d x

\frac{1}{2} arcsec (\frac{1}{2} x) + C

Solution steps

\int \frac{1}{x x ^{2} - 2} d x

Apply Trigonometric Substitution

: \int \frac{1}{2} d u

= \int \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 d u

Integral of a constant:

\int a d x = a x

= \frac{1}{2} \cdot 1 \cdot u

Substitute back

u = arcsec (\frac{1}{2} x)

= \frac{1}{2} \cdot 1 \cdot arcsec (\frac{1}{2} x)

Simplify

= \frac{1}{2} arcsec (\frac{1}{2} x)

Add a constant to the solution

= \frac{1}{2} arcsec (\frac{1}{2} x) + C

f (x) = 8 x - 3 x^{2}

(x^{2} + 1) \cdot \frac{d y}{d x} + 6 x (y - 1) = 0, y (0) = 3

\frac{d y}{d t} = \frac{1}{2 y + 1}

f (x) = \frac{x}{x + 1}, at x = 1

\frac{d}{d x} (2 x^{2} y)

What is the integral of 1/(xsqrt(x^2-2)) ?
The integral of 1/(xsqrt(x^2-2)) is 1/(sqrt(2))arcsec(1/(sqrt(2))x)+C