What is the integral from-infinity to-1 of x^{-16/7} ?

The integral from-infinity to-1 of x^{-16/7} is diverges

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integral from-infinity to-1 of x^{-16/7}

\int_{- \infty}^{- 1} x^{- \frac{16}{7}} d x

diverges

Solution steps

\int_{- \infty}^{- 1} x^{- \frac{16}{7}} d x

Compute the indefinite integral:

\int x^{- \frac{16}{7}} d x = - \frac{7}{9 x ^{\frac{9}{7}}} + C

Compute the boundaries:

\int_{- \infty}^{- 1} x^{- \frac{16}{7}} d x =

diverges

= diverges

\int csc (\frac{t}{4}) cot (\frac{t}{4}) d t

\int tan^{3} (t) sec^{2} (t) d t

\frac{x ^{2}}{( 1 + x )}

\frac{s}{( s + 1 ) ^{2}}

\frac{d}{d z} (\frac{x}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}})

What is the integral from-infinity to-1 of x^{-16/7} ?
The integral from-infinity to-1 of x^{-16/7} is diverges