What is the integral from 0 to 2 of 1/(x^2) ?

The integral from 0 to 2 of 1/(x^2) is diverges

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integral from 0 to 2 of 1/(x^2)

\int_{0}^{2} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{2}

= [- \frac{1}{x}]_{0}^{2}

Compute the boundaries:

diverges

= diverges

\frac{\partial}{\partial x} (e^{x y} sin (x yz))

t^{2} y^{^{''}} - 7 t y^{^{'}} + 15 y = 0

x \to \infty lim (x ln (x))

\frac{s ^{2}}{s ^{3} - 1}

\int x (3 x + 2) d x

What is the integral from 0 to 2 of 1/(x^2) ?
The integral from 0 to 2 of 1/(x^2) is diverges