What is the derivative of (x-3/2) ?

The derivative of (x-3/2) is 1/2

What is the first derivative of (x-3/2) ?

The first derivative of (x-3/2) is 1/2

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\frac{d}{d x} (\frac{x - 3}{2})

\frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{x - 3}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d x}{d x} - \frac{d}{d x} (3))

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= \frac{1}{2} (1 - 0)

Simplify

= \frac{1}{2}

\int 6 x^{5} - 4 x^{4} - 9 x^{2} d x

\int (2 x^{3} - 9 x^{2} + 5 x) e^{- x} d x

\int \frac{x}{2 ( x ^{2} + 1 )} d x

\frac{d}{d x} (\frac{e ^{x} + e ^{- x}}{x ^{3}})

y^{3} - (14 x + 8) + 3 x y^{2} \frac{d y}{d x} = 0

What is the derivative of (x-3/2) ?
The derivative of (x-3/2) is 1/2
What is the first derivative of (x-3/2) ?
The first derivative of (x-3/2) is 1/2