What is the integral from 0 to infinity of 8sin^2(a) ?

The integral from 0 to infinity of 8sin^2(a) is diverges

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integral from 0 to infinity of 8sin^2(a)

\int_{0}^{\infty} 8 sin^{2} (a) d a

diverges

Solution steps

\int_{0}^{\infty} 8 sin^{2} (a) d a

Compute the indefinite integral:

\int 8 sin^{2} (a) d a = 4 (a - \frac{1}{2} sin (2 a)) + C

Compute the boundaries:

\int_{0}^{\infty} 8 sin^{2} (a) d a =

diverges

= diverges

y^{^{''}} - 10 y^{^{'}} + 25 y = e^{5 x}

\int_{0}^{2} 144 x + 289 d x

16 4 4 x^{4} + 4

t^{3} - \frac{1}{4 t ^{7}}

\frac{\partial}{\partial y} (y^{2} sin (x))

What is the integral from 0 to infinity of 8sin^2(a) ?
The integral from 0 to infinity of 8sin^2(a) is diverges